# Line slope calculator 3x+8y=48

**Straight line given by points A[0; 6] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.375x+6

**Canonical form of the line equation:**3x+8y-48 = 0

**Parametric form of the line equation:**

x = 8t

y = -3t+6 ; t ∈ R

**Slope:**m = -0.375

**Slope angle of line: φ =**-20°33'22″ = -0.3588 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 5.618

**The length of the segment AB: |AB| =**8.544

**Vector: AB =**(8; -3)

**Normal vector: n =**(3; 8)

**Midpoint of the segment AB: M =**[4; 4.5]

**Perpendicular Bisector equation:**8x-3y-18.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 69°26'38″ = 1.212 rad**